Find the quadratic function y = ax^2 bx c whose graph passes through the given points (−1,−3), (3,25), (−2,5) Hint Substitute each point into y= ax^2Hi Elliot The inverse of a function f is a function g such that g(f(x)) = x So if you have the function f(x) = ax 2 bx c (a general quadratic function), then g(f(x)) must give you the original value xYou should already see the problem there will be two functions, not one, since a function must provide a unique value in its range for each value in its domain and a quadratic maps twoThe "formula" for a parabola (in the conic sections form) is mathx^2=4cy/math (although some textbooks use mathp/math instead of mathc/math, so mathx^2=4py/math) If you put your equation into that form you can make some observatio
A Tangent To A Quadratic
